如果XY=8分之3则X与Y成什么比例
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/06 12:29:05
3/x-2/y=3等式两边同乘以xy3y-2x=3xy(2x-3y-xy)/(7xy+9y-6x)=[-(3y-2x)-xy]/[3(3y-2x)+7xy]=(-3xy-xy)/[3·(3xy)+7x
1/x+1/y=2则(2x+3xy+2y)/(x-xy+y)分子分母同除以xy=(2/x+2/y+3)/(1/x+1/y-1)=(4+3)/(2-1)=7
由1/x-1/y=3得(y-x)/xy=3题中的式子分子分母同时除以xy得(2/y+3-2/x)/(1/y-2-1/x),通分得【2(x-y)/xy+3】/【(x-y)/xy-2】代入得3/5
xy/(x+y)=2解得xy=2(x+y)所以(3x-5xy+3y)/(-x+3xy-y)=(3/2*xy-5xy)/(-1/2*xy+3xy)=-7/5
已知x分之1-y分之1=3,则有y-x=3xy(5x+xy-5y)/(x-xy-y)=7/2
x-3xy-Y分之3x+5xy-3y==(3x+5xy-3y)/(x-3xy-Y)=(5+3*(1/y-1/x))/(-3+(1/y-1/x)).分子分母同时除以xy=(5-21)/(-3-7).将x
-½x^3y+mx^3y=0如果-½x^3y与mx^3y互为相反数,则m=__1/2___(xy≠0)提交回答
(5x+3xy-5y)/(x-2xy-y)=(5/y+3-5/x)/(1/y-2-1/x)分子分母同时除以xy=[-5(1/x-1/y)+3]/[-(1/x-1/y)-2]=(-15+3)/(-3-2
xy/(x+y)=2∴xy=2(x+y)(3xy-x-y)/(3x-5xy+3y)=[6(x+y)-x-y]/[3x+3y-10(x+y)]=5(x+y)/[-7(x+y)]=-5/7
因为X+Y分之XY=2,所以XY=2(X+Y)代入后面的分子式得:13(X+Y)/5(X+Y)=13/5
1/x-1/y=3(y-x)/(xy)=3y-x=3xy(x-2xy-y)/(2x+3xy-2y)=[-(y-x)-2xy]/[-2(y-x)+3xy]=(-3xy-2xy)/(-6xy+3xy)=5
可如图写出期望计算式,其中只有一项不为0.经济数学团队帮你解答,请及时采纳.谢谢!
在1/x+1/y=3的两边分别乘以xy,则y+x=3xy.将此代入所求的式子,有(3*3xy+xy)/(3xy-xy)=5比反了,抱歉啊!
2分之1或负4分之3
xy/(x+y)=2(x+y)/xy=1/21/x+1/y=1/2(3x-xy+3y)/(-x+3xy-y)=(3/y-1+3/x)/(-1/y+3-1/x)=[3(1/x+1/y)-1]/[(3-(
x分之1-y分之1=-3所以(y-x)/xy=-3y-x=-3xy从而3x-2xy-3y分之x+3xy-y=(3xy+3xy)/(3×3xy-2xy)=6/7
x分之1-y分之1=3(y-x)/xy=3y-x=3xy(2x+3xy-2y)/(x-2xy-y)=[3xy-2(y-x)]/[-2xy-(y-x)]=(3xy-6xy)/(-2xy-3xy)=(-3
x除以x的绝对值+y除以y的绝对值=0,因为分母不能为0所以x除以x的绝对值与y除以y的绝对值异号所以x与y异号所以-xy>0;y分之x<0,所以-xy<y分之x
等式两边除以xy所以1/y-1/x=1