圆X平方加Y平方减4X加6Y=0的圆心坐标-搜答案-神马作文网

再答：谢谢

把25拆成16+9(x²-8x+16)+(y²+6y+9)=0(x-4)²+(y+3)²=0平方大于等于0,相加等于0若有一个大于0,则另一个小于0,不成立.所

即(x²+4x+4)+(y²-6y+9)=0(x+2)²+(y-3)²=0所以x+2=0,y-3=0x=-2,y=3所以x-y=-5

=9x^2+6x+1-(4y^2+4y+1)=(3x+1)^2-(2y+1)^2

题目肯定有问题,不用纠结了.条件x(y-1)-y(x-1)=4可等价的写为y-x=4.但是对于满足y-x=4的x,y,x²+y²可以有无穷多种取值.例如x=1,y=5满足条件,相应

x^2+y^2=6y-4x-13x^2+4x+4+y^2-6y+9=0(x+2)^2+(y-3)^2=0x=-2y=3x^2-y^2=(-2)^2-3^2=4-9=-5

过两圆心的直线再答：y=3x-9

x平方加y平方减2xy减6x加6y加9=0x^2+y^2-2xy-6x+6y+9=0(x^2+y^2-2xy)-6(x-y)+9=0(x-y)^2-6(x-y)+9=0(x-y-3)^2=0x-y-3

x的平方加y的平方减4x加6y加13等于0x^2+y^2-4x+6y+13=0(x^2-4x+4)+(y^2+6y+9=0(x-2)^2+(y+3)^2=0x-2=0,y+3=0x=2,y=-3x+y

x^2+y^2-6x+4y+13=0x^2-6x+9+y^2+4y+4=0(x-3)^2+(y+2)^2=0又因为(x-3)^2>=0;(y+2)^2>=0;所以(x-3)^2=0,(y+2)^2=0

是要化简吗再答：

zenmuhuo：∵4x²-4x+y²+6y+10=04x²-4x+1+y²+6y+9=0(2x-1)²+(y+3)²=0且(2x-1)&s

x^2-4xy+4y^2-3x+6y+2=(x-2y)^2-3(x-2y)+2=(x-2y-1)(x-2y-2)

x^2+4x+y^2-2y+5=0(x^2+4x+4)+(y^2-2y+1)=0(x+2)^2+(y-1)^2=0x=-2,y=1x^2+y^2=(-2)^2+1^2=4+1=5

[(x²+y²-9)²-4x²y²]/(x²+6x+9-y²)=(x²+2xy+y²-9)(x²-2

4x平方加y平方-4x+6y+10=(2x-1)^2+(y+3)^2=02x-1=0y+3=0x=1/2y=-3x^2+y^2=1/4+9=37/4

X的平方-4X+4+Y的平方+6+9=0（X-2）的平方+（Y+3）的平方=0X=2Y=-3

(x^2+y^2)^2-4x^2y^2=(x^2+y^2+2xy)(x^2+y^2-2xy)=(x+y)^2*(x-y)^2=(x^2-y^2)^2数学佰亊嗵为你解答,希望我的回答为您带来帮助!