因式分解y³ x²y-3xy²-搜答案-神马作文网

xy+x+y+1因式分解

(x+1)(y+1)

解题思路：提取公因式进行分解解题过程：附件最终答案：略

解题思路：本题主要利用完全平方公式进行因式分解即可求出结果解题过程：解:x²－6xy＋9y²=(x-3y)2

楼主题目没写错么?最后一项是不是y^3?否则没法分解,我用mathematica试过了.参考文献：Mathematica7.0里面的Factor函数,可直接对多项式因式分解

(x-y)²-(3x-3xy+y²)=x²+y²-2xy-3x+3xy-y²=x²-3x+xy=x(x+y-3)

2x-2y+3xy(x-y)=2(x-y)+3xy(x-y)=(x-y)(2+3xy)

x^3+x^2y-xy^2-y^3=（x-y）(x^2+xy+y^2)+xy(x-y)=(x-y)(x^2+y^2+2xy)=(x-y)(x+y)^2

=3（x+y)2

x^2-2xy-3y^2+x+y=x*x-2*x*y-3*y*y+x+y=(x-3y)(x+y)+(x+y)=(x+y)(x-3y+1)如果是初中生,分解到这里就可以了如果是高二及以上,可能要在复数范

因式分解x2+y-xy-x

x²＋y－xy－x＝﹙x²－xy﹚＋﹙y－x﹚＝x﹙x－y﹚－﹙x－y﹚＝﹙x－y﹚﹙x－1﹚

我的回答满意吗?再答：再答：望采纳！再答：图片正在发送再答：发过去了再答：看不懂可以问我

符号好像有问题.x³+x²y-xy²-y³=x²(x+y)-y²(x+y)=(x+y)(x²-y²)=(x-y)(x+y

因式分解x^3y-xy^3

=xy(x^2-y^2)=xy(x+y)(x-y)

1-x-y+xy 因式分解

1-x-y+xy=(1-x)-(y-xy)=(1-x)-y(1-x)=(1-x)(1-y)

因式分解xy-x-y+1

xy-x-y+1=x(y-1)-y+1=x(y-1)-(y-1)=(y-1)(x-1)

y^3+xy^2+2xy+x^2-1=(x+y-1)(x+y^2+y+1)再问：烦写出过程再答：

xy-x-y+1因式分解

(x-1)(y-1)

x²y+3xy²-x-3y=xy(x+3y)-(x+3y)=(x+3y)(xy-1)

原式=xy(x-y)+(x-y)(x^2+xy+y^2)=(x-y)(x^2+2xy+y^2)=(x-y)(x+y)^2

-x³y³-x²y²-xy=-xy(x²y²+xy+1)