因式分解1-12x^2y^2 48x^4y^4

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因式分解1-12x^2y^2 48x^4y^4
4(x+y)^2-20(x+y-1)+5因式分解

4(x+y)^2-20(x+y-1)+5=4(x+y)^2-20(x+y)+20+5=4(x+y)^2-20(x+y)+25=[2(x+y)]^2-2*[2(x+y)]*5+5^2=[2(x+y)-5

(x-y)^2-(x-y)^3因式分解

(x-y)^2-(x-y)^3=(x-y)^2[1-(x-y)]=(x-y)^2(1-x+y)2.(x+y)^2-(x+y)^3=(x+y)^2[1-(x+y)]=(x+y)^2(1-x-y)3、(x

9(x+y)^2-6(x+y)+1进行因式分解

9(x+y)^2-6(x+y)+1=【3(x+y)-1】²

因式分解(2x -y) -4x +2y+1

是(2x-y)²-4x+2y+1原式=(2x-y)²-2(2x-y)+1=(2x-y-1)²

(x-1)²-2y(x-1)+y²因式分解

(x-1)²-2y(x-1)+y²=x²-2x+1-2xy+2y+y²=x²-2xy+y²-2x+2y+1=(x-y)²-2(x-

把4(x-y+1)+y(y-2x)因式分解

4(x-y+1)+y(y-2x)=4x-4y+4+y^2-2xy=(y^2-4y+4)-2x(2-y)=(y-2)^2+2x(y-2)=(y-2)(2x+y-2)

x^2(x^2-y^2)-12y^4因式分解

x^2(x^2-y^2)-12y^4=x^4-x^2y^2-12y^4=(x^2-4y^2)(x^2+3y^2)您好,很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,

因式分解1:(x^2-9y^2)-(x+3y)

1:(x^2-9y^2)-(x+3y)=(x+3y)(x-3y)-(x+3y)=(x+3y)(x-3y-1)提取公因式2:(a-b)^4-(b-a)^2=(a-b)^4-(a-b)^2=(a-b)^2

1-x-y+xy 因式分解

1-x-y+xy=(1-x)-(y-xy)=(1-x)-y(1-x)=(1-x)(1-y)

因式分解(x-y)^2-x-y

=(x+y)(x-y)-(x+y)=(x+y)(x-y-1)

因式分解xy-x-y+1

xy-x-y+1=x(y-1)-y+1=x(y-1)-(y-1)=(y-1)(x-1)

9(X+Y)^2-6(X+Y)+1 (因式分解)

原式=(3x+3y-1)(3x+3y+1)标准的十字相乘法.

因式分解(x+y)的平方+2(x+y)+1

(x+y)的平方+2(x+y)+1=(x+y)²+2×(x+y)×1+1²=(x+y+1)²

x^2+y^2-x-y-xy+1如何因式分解

好像不能分解!看看原题?再问:原题是比较x^2+y^2+1与x+y+xy的大小。。。再答:x、y的关系或取值条件没有给出?用作差法比较x^2+y^2+1-(x+y+xy)=x^2-2xy+y^2+xy

25(x-y)^2-1因式分解

25(x-y)^2-1=﹝5(x-y)+1﹞﹝5(x-y)-1﹞

3x-y^2 因式分解

这个不能分解的,题目错了

(xy-x-y+1)^2因式分解

xy-x-y+1=x(y-1)-(y-1)=(x-1)(y-1)(xy-x-y+1)^2=(x-1)^2(y-1)^2

因式分解(x-2y)^2-12(x-y)+36

(x-2y)^2-12(x-y)+36=(x-2y)^2-12(x-2y+y)+36=(x-2y)^2-12(x-2y)-12y+36=(x-2y-6)^2-12y=(x-2y-6)^2-(2√3y)