3xy=3x*y是因式分解吗?-搜答案-神马作文网

4xy²-4x²y-y^3=y(4xy-4x²-y²)=-y(4x²-4xy+y²)=-y(2x-y)²

楼主题目没写错么?最后一项是不是y^3?否则没法分解,我用mathematica试过了.参考文献：Mathematica7.0里面的Factor函数,可直接对多项式因式分解

(x-y)²-(3x-3xy+y²)=x²+y²-2xy-3x+3xy-y²=x²-3x+xy=x(x+y-3)

2x-2y+3xy(x-y)=2(x-y)+3xy(x-y)=(x-y)(2+3xy)

x^3+x^2y-xy^2-y^3=（x-y）(x^2+xy+y^2)+xy(x-y)=(x-y)(x^2+y^2+2xy)=(x-y)(x+y)^2

=3（x+y)2

x^2-2xy-3y^2+x+y=x*x-2*x*y-3*y*y+x+y=(x-3y)(x+y)+(x+y)=(x+y)(x-3y+1)如果是初中生,分解到这里就可以了如果是高二及以上,可能要在复数范

（x+y）(x+2y)=x²+xy+2xy+2y²=x²+3xy+2y²

我的回答满意吗?再答：再答：望采纳！再答：图片正在发送再答：发过去了再答：看不懂可以问我

符号好像有问题.x³+x²y-xy²-y³=x²(x+y)-y²(x+y)=(x+y)(x²-y²)=(x-y)(x+y

x^2+y^2+3-xy-3y＝(x^2-xy+y^2/4)+3(y^2/4-y+1)=(x-y/2)^2+3(y/2-1)^2

这题偶也不会饿,不过为什么一定要用轮换做,我最后2题就不是用轮换的,哈哈,饿,我好像飘太多次了,汗,我该闪了,可是左闪,还是右闪?不对应该是按右上发的叉闪(偶废话好多),闪!大叉偶来也>P.S请无视我

因式分解x^3y-xy^3

=xy(x^2-y^2)=xy(x+y)(x-y)

(x-5y)(x+2y)

x²-xy+2x-y-3=x(x-y)+(x-y)+x-3=(x-1)(x-y)+x-3=(x-1)(x-y-1)-2x²-xy+2x+y-3=x(x-y)-(x-y)+3(x-1

y^3+xy^2+2xy+x^2-1=(x+y-1)(x+y^2+y+1)再问：烦写出过程再答：

x²y+3xy²-x-3y=xy(x+3y)-(x+3y)=(x+3y)(xy-1)

3x^2y-3xy-6y=3y(x²-x-2)=3y(x-2)(x+1);很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,再问：我算出来是y（x-6）（x+

原式=xy(x-y)+(x-y)(x^2+xy+y^2)=(x-y)(x^2+2xy+y^2)=(x-y)(x+y)^2

-x³y³-x²y²-xy=-xy(x²y²+xy+1)