2x-y=4和x-2y=5-搜答案-神马作文网

原式=(9x²+24xy+16y²-4x²+y²-5x²+6xy-y²)÷(-2y)=(30xy+16y²)÷(-2y)=-15x

(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=4x-2y-z-5x[6y-(x+y)]+x-(3y-10z)=4x-2y-z-30xy+5x²+5xy+x-3

很多数学符号,还是写出来方便.

2X^2-xy-5x+y+4=o可化为：（x^2-4x+4）+(X^2-XY-X+Y)=0(X-2)^2+(x-Y)(x-1)=0因为x>=YY>=1所以X-Y>=0x-1>=0又因为(X-2)^2>

X比Y=5比2正比例

化简得：-x+7y=11①7x+3y=27②①式×7得：-7x+49y=77③②+③得：52y=104∴y=2代入①得：x=3∴x=3,y=2再问：亲，是代入法哦！再答：代入法①式得3x+3y-4x+

2X^2－XY－5X+Y+4=X^2+X(X-Y)-4X-X+Y+4=(X-2)^2+(X-1)(X-Y)=0x≥y≥1(x-2)^2>=0,x-1>=0,x-y>=0,即(x-1)(x-y)>=0两

楼上的全错,{(3x+y)(3x-y)-(x-5y)(5x-y)-(x-2y)²}÷(-4x)={9X²-(5x²-xy-25x²+5y²)-(x&s

(x*x+y*y)(x*x+y*y)-4x*x*y*y=(x^4-2x^2y^2+y^4)=(x^2-y^2)^2=0x^2=y^2x/y=±1(x*x+5xy+y*y)/(x*x+2xy+y*y)=

实数x、y,满足x≥y≥1,2x^2-xy-5x+y+4=0,则2x^2-5x+4=(x-1)y≤(x-1)x,即2(x-2)^2≤0,x=2,y=2.

3x+4y=2可知x=（2-4y)/3y=(2-3x)/4分别代入x-y5/7x

因为(x-y)/(x+y)=3,则(x＋y)/(x－y)＝1/3则5(x-y)(x+y)-(x+y)/2(x-y)＝5*3-1/(3*2)=15-1/6=89/6

应该是4x+2y=304x+y=22吧再问：��x��y�ֱ��Ƕ��١�再答：4x+2y=224x+y=30�ó�y=22-30=-8��y=-8��뵽4x+2y=22�еó�4x+��-16��

X^2表示平方X^2+4X+4+Y^2-2Y+1=0(X+2)^2+(Y-1)^2=0因为平方大于=0所以X+2=0Y-1=0X=-2Y=1X^2+Y^2=5

应该求（x+y+z）/y(x+y+z)/(y-x)已知x/3=y/5=z/4x/y=5/3z/y=5/4x/z=4/3代进去就好了比如第一个X/Y+1+Z/Y=5/3+1+4/3=4再问：x/y=5/

3X+4Y=23X=2-4YX=(2-4Y)/3X-Y-1/7D

1,-3再问：过程。。。再答：★（x²－2x)+（y²－4y）=5★（x－1）²+（y－2）²=1+4－5★（x－l）²=0,（y－2）²=

(x+y)/2+(x-y)/6=1x/2+x/6+y/2-y/6=12x/3+y/3=12x+y=3(1)3(x+y)-4(x-y)=43x+3y-4x+4y=4-x+7y=4(2)(1)+2*(2)

原式=x-x+x-x+……-x+(2-1+4-3+5-4+……+2008-2007-2009）y=0+(1×1004-2009)y=-1005y=1005/2