2x-1分之2=4x方-1

(x+2)/(x-2)-1=3/(x²-4)(x+2-x+2)/(x-2)=3/(x-2)(x+2)(x≠2)4=3/(x+2)4x+8=34x=-5x=-5/4你的题目不够清晰

(x+1)/x²-2x²/(x+1)=1设(x+1)/x²=t,则方程变为：t-2/t=1,即：t²-t-2=0,即(t-2)(t+1)=0∴t1=2t2=-1

x-x分之1=3x^2-2+1/x^2=9x^2+1/x^2=11x^4+1=11x^2x^4=11x^2-1x-x分之1=3x^2-1=3xx^2=3x+1x的四次方-2x的三次方-2x的二次方-7

x/(1-x)+x/(1+x)+2x/(1+x^2)+4x/(1+x^4)=0[x(1+x)+x(1-x)]/(1-x^2)+2x/(1+x^2)+4x/(1+x^4)=02x/(1-x^2)+2x/

1,去分母,等号两边同时乘以3x+33x=2x+12（3x+3）去括号移项,合并同类项,系数化为12.等号左右同乘x方-12（x+1）=4x=1,检验x=1时,方程分母为0,所以x=1是方程的增根,方

化简结果：-X的3次方分之一乘以（5X方-4分之1乘以X+2分之1）

(x-2)/(x+2)-1=3/(x²-4)[(x-2)-(x+2)]/(x+2)=3/[(x-2)(x+2)]-4/(x+2)=3/[(x-2)(x+2)]-4(x-2)=3x=-5/4代

x+3分之2+2分之3=2x+6分之7两边乘以2(x+3)得4+3(x+3)=74+3x+9=73x=-6∴x=-2经检验：x=-2是方程的根（x方-1分之x方-4x）+1=x+1分之2x两边乘以(x

（x^2+2x+1）/(x^2-3x-4)=(x+1)^2/(x+1)(x-4)=(x+1)/(x-4)

把每个式子因式分解x的方+5x+4=（x+1）(x+4)x方-5x+6=(x-2)(x-3)………………

2X-X分之1-2X方-1分之4X=32X-(1/X)-[4X/(2X^2-1)]=3[(2X^2-1)/X]-[4X/(2X^2-1)]=3设K=2X^2-1)/X,则K-4/K=3K^2-3K-4

x/(1-x)+x/(1+x)+2x/(1+x^2)+4x/(1+x^4)=[x(1+x)+x(1-x)]/(1-x^2)+2x/(1+x^2)+4x/(1+x^4)=2x/(1-x^2)+2x/(1

=(x-4)/(x+1)(x-1)除以(x-4)(x+1)/(x+1)平方+1/(x-1)=(x-4)/(x+1)(x-1)乘以(x+1)平方/(x-4)(x+1)+1/(x-1)=(x-4)/(x+

(x-1)/(x^2+3x+2)+6/(2+x-x^2)-(10-x)/(4-x^2)=(x-1)/(x+1)(x+2)-6/(x+1)(x-2)-(x-10)/(x+2)(x-2)=[(x-1)(x

x/(x²+2x+1),(x-1)/(x²+x),1/(x²-1)式1：x/(x+1)²,式2：(x-1)/[x(x+1)],式3：1/[(x+1)(x-1)]

x＝4084y＝1＆＃47；9所以√x＝2√y＝1＆＃47；3原式＝4＊（1＆＃47；2）－2＆＃47；3－9＊y√y＝2－2＆＃47；3－1＆＃47；3＝1

原式=[(x+2)/x(x-2)-(x-1)/(x-2)²]×x/(x-4)=[(x²-4-x²+x)/x(x-2)²]×x/(x-4)=[(x-4)/x(x-

=(x+2)/(x²-4)+(x-2)/(x²-4)+(x平方+4)分之2x+(x四次方+16)分之4x三次方=2x/(x²-4)+(x平方+4)分之2x+(x四次方+1

由x二次方-x+4分之1=0得x=1/2x+2分之1=1再问：你怎么算的，不过谢谢

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