2sin50° sin10°(1 根号3*tan10°
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/25 10:43:31
原式=[2sin50°+2sin10°*sin(10°+30°)/cos10°]*√2sin80°=[2cos40°+2sin10°sin40°/cos10°]*√2cos10°=2√2(cos40°
[2sin50°+sin10°(1+√3tan10°)]•√(2sin²80°)=[2sin50+sin10(cos10+√3sin10)/cos10]•√2sin8
和差化积,如果不是数学,用计算器可以满足工程要求
[2sin50°+sin10°(1+根号3tan10°)]乘sin10°=[2sin50°+sin10°(1+√3sin10º/cos10º)]sin10º=[2sin5
注:题目似乎多乘了一个sin80°![2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)=[2sin50°+sin10°(1+√3tan10°)]*√2(cos10°)=√2
【2sin50+sin10(1+√3tan10)】*√(2(sin80)^2)=【2sin50+sin10(1+√3Sin10/Cos10)】*√(2(sin80)^2)=【2sin50+sin10(
[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80度)=[2sin50°*sin80°+sin10°*cos10°(cos10°+√3sin10°)/cos1
【2sin50+sin10(1+√3tan10)】*√(2(sin80)^2)=【2sin50+sin10(1+√3Sin10/Cos10)】*√(2(sin80)^2)=【2sin50+sin10(
原式=(1-cos20)/2+(1-coxs100)/2+sin10sin(10+40)=1-1/2(cos20+cosx100)+sin10^2cos40+sin10cos10sin40=`````
根据三角函数积化和差公式sinαsinβ=-[cos(α+β)-cos(α-β)]/2
[2sin50+sin10(1+根号3*tan10)]根号(sin^2(80))=[2sin50+sin10(1+根号3*sin10/cos10)]sin80=[2sin50+sin10(1+根号3*
原式=[2sin(60-10)+sin10+(√3)sin2(10)/cos10]sin(90-10)用公式sin(A-B)=sinAcosB-cosAsinB=[(√3)cos10-sin10+si
=sin10sin50-sin70sin10-sin50sin70=sin10{sin(60-10)-sin(60+10)}-sin(60-10)sin(60+10)=sin10(-2sin10*co
1+根号3tan10°=(cos10°+根号3sin10°)/cos10°=2(1/2×cos10°+1/2×根号3sin10°)/cos10°=2(cos60°cos10°+sin60°sin10°
[2sin50°+sin10°(1+√3tan10°)]•√(2sin²80°)=[2sin50+sin10(cos10+√3sin10)/cos10]•√2sin8
[2sin50°+sin10°(1+√3tan10°)]•√(2sin²80°)=[2sin50+sin10(cos10+√3sin10)/cos10]•√2sin8
1-sin²10=cos²10所以原式=(2sin50+sin10+√3sin10*sin10/cos10)*cos10=2sin50cos10+sin10cos10+√3sin&
原式=[2sin50°+sin10°(1+3sin10°cos10°)]1+cos20°=(2sin50°+sin10°•cos10°+3sin10°cos10°)1+cos20°=(2sin50°+
2sin50°+sin10°[1+√3tan10°)√(1+cos20°)=[2sin50°+sin10°*(cos10°+√3sin10°)/cos10°]*√2cos10°=2√2sin50°co
[2sin50°+sin10°(1+√3tan10°)]√(2sin80°)=[2sin50+sin10(cos10+√3sin10)/cos10]√2sin80=[2sin50cos10+2sin1