25分之x的平方-16分之y的平方因式分解-搜答案-神马作文网

(x²/25)÷(y²/16)=16x²/(25y²)再问：抱歉，请问能分解因式吗？再答：你这个题不是分解因式的类型，如果改为：(x²/25)-(y&

原式=2xy/(x+y)(x-y)+x(x-y)/(x+y)(x-y)=(2xy+x²-xy)/(x+y)(x-y)=(x²+xy)/(x+y)(x-y)=x(x+y)/(x+y)

（x的平方-y的平方)分之2xy+(x+y)分之x-(y-x)分之y=（x的平方-y的平方)分之2xy+(x+y)分之x+(x-y)分之y=(x²-y²)分之[2xy+x(x-y)

=x(x-y)/xy²×y/[-(x-y)]=-1/y

（x分之x-y）-（y分之x+y）+（2xy分之x的平方-y的平方）=1-y/x-1-x/y+(x^2-y^2)/2xy=-2(y^2+x^2)/2xy+(x^2-y^2)/2xy=-(x^2+3y^

①49分之1的x的平方-25分之16y的平方=（x/7+4y/5）（x/7-4y/5）②-0.01+四分之九（a的平方）=(3a/2-0.1)(3a/2+0.1)③49（a-b）的平方-16（a+b）

y=[根号下（x^2-9)+根号下(9-x^2)+16^(1/4)]/(3-x)所以：x^2-9=0,9-x^2=0,3-x不等于0解得：x=-3,代入,求得：y=1/3所以：x/y=-3÷(1/3)

2/(x-y)-(x+y)/(x-y)^2=[(2x-2y)-(x+y)]/(x-y)^2=(x-3y)/(x-y)^2

原式=xy/(x-y)(x+y)÷(2y)/(x-y)(x+y)=x/2再问：再问：

(x^2-4y^)\(x+y)^2乘以2x(x+y)/(x+2y)=2x(x-2y)\(x+y)

(8x^2/9y^2)*(3y/-4x)=-2x/3y不懂请追问,满意请采纳~再问：过程？？？？再答：就相当于（8x的平方除以-4x）乘以(3y除以9y的平方）=-2x乘以3y分之一=负的3y分之2x

（x/2y）²×（y/2x）-x/y²÷（2y²/x）=x²/2y×（y/2x）-（x/y²）×（x/2y²）=x/8y-x²/（

[1/(x-y)-1/(x+y)]/[xy^2/(x^2-y^2)]=[(x+y-x+y)/(x-y)(x+y)]/[xy^2/(x-y)(x+y)]=[2y/(x-y)(x+y)]/[xy^2/(x

(1)2xy的平方分之3x的平方y=(2y)分之3x（注：分子分母约掉xy）.(2)（x的平方-25）分之（x+5）=[(x-5)(x+5)]分之（x+5）=(x-5)分之1

平方差=[(3x-2y)/2+(3x+2y)/2][(3x-2y)/2-(3x+2y)/2]=[(3x-2y+3x+2y)/2][(3x-2y-3x-2y)/2]=3x*(-2y)=-6xy

现将括号里的通分x2-y2可约去最后的y分之2再问：能具体一点吗再答：原式=((x+y+x-y)/(x2-y2)÷（x的平方-y的平方分之xy）=2x/(x2-y2)×(x2-y2)/xy=y分之2只

（1-y+x分之y）÷y的平方-x的平方分之x=[(y+x-y)/(y+x)]÷x/(y²-x²)=x/(y+x)*[(y+x)(y-x)/x]=y-x

x的平方-64y的平方分之2x-x-8y分之1=[2x-(x+8y)]/(x-8y)(x+8y)=(x-8y)/(x-8y)(x+8y)=1/(x+8y)

x-y分之2x的平方-y-x分之x的平方-4xy+x-y分之2y的平方-x的平方=2x/(x-y)-(x²-4xy)/(y-x)+(2y-x²)/(x-y)=(2x+x²