化简求值2分之1a-2a-3分之1b方
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/21 12:46:27
原式=(a-2)/a(a+2)-(a-1)/(a+2)平方=(a平方-2a-a平方+a)/a(a+2)平方=-1/(a+2)平方=-1/5
=1/(a+2)+4/(a+2)(a-2)=(a-2+4)/(a+2)(a-2)=1/(a-2)=1/(2+√3-2)=√3/3
(a²-4a+3)分之(a²-4)×(a²+3a+2)分之(a-3)-(a²-1)分之(a+3)=(a+2)(a-2)/(a-3)(a-1)x(a-3)/(a+
a=1/(2+√3)=2-√3∴a
(a+1分之1-a的平方-1分之a-2)除以a+1分之1=1/(a+1)x(a+1)-(a-2)/(a+1)(a-1)x(a+1)=1-(a-2)/(a+1)=(a+1-a+1)/(a+1)=2/(a
a=2/﹙1-√3﹚=﹣﹙√3+1﹚﹙a²-1﹚/﹙a-1﹚+√﹙a²+2a+1﹚/﹙a²+a﹚-1/a=a+1-1/a-1/a=a+1-2/a=﹣√3-1+1+2/﹙√
a²-a-3=0所以a²=a+3原式=a²(a-3)/(a-2)÷[5-(a+2)(a-2)]/(a-2)=a²(a-3)/(a-2)×[-(a-2)/(a+3
a=根号2-1∴a-1
4a^2-(2a^2+a-1)+(2a^2+3a)=4a^2-2a^2-a+1+2a^2+3a=4a^2+2a+1=1
解1/(a+1)-(a+1)/(a²-2a+1)÷(a+1)/(a-1)=1/(a+1)-(a+1)/(a-1)²×(a-1)/(a+1)=1/(a+1)-1/(a-1)=(a-1
(a+2a+1)/(a-1)-a/(a-1)=(a+1)^2/(a+1)(a-1)-a/(a-1)=(a+1)/(a-1)-a/(a-1)=1/(a-1)由a=根号3+1,所以原式=1/(a-1)=1
原式=(a+1)/(a-1)-[a/(1/a)]/(a²-2a+1)=(a+1)/(a-1)-a²/(a-1)²=[(a+1)(a-1)-a²]/(a-1)&s
化简求值(a+b)的立方-4ab(a+b),其中a=-2分之1,b=4分之3原式=(a+b)((a+b)²-4ab)=(a+b)(a²+b²-2ab)=(a+b)(a-b
原式=2√a-(a+√a)/(a-√a)=2√a-√a(√a+1)/[√a(√a-1)]=2√a-(√a+1)/(√a-1)分母有理化=2√a-(√a+1)²/[(√a+1)(√a-1)]=
a^2-1+2-1/a=a^2-1/a+1,a=-3代入,得原式=31/3
加点括号吧,求你了再问:(a方+2a+1)分之(a方-1)+(a-2)分之(2a-a方)除以(a)其中a=(根号2)+1再答:不知你的“除以(a)”是啥意思?除在哪里?只能给你下式(a^2-1)/(a