化简求值2 3x*根号9x-x平方-搜答案-神马作文网

x^2-9>=09-x^2>=0x=3或-3x=3不合题意,舍去x=-3y=(0+0+1)/(-3-3)=-1/6

[3x/(x-1)-x/(x+1)]÷x/(x²-1)=[3x/(x-1)-x/(x+1)]*(x²-1)/x=[3x/(x-1)]*(x²-1)/x-[x/(x+1)]

(x√x+x√y)÷(xy-y²)-(x+√xy+y)÷x×√x-y×√y=(1+2)÷(4-16)-(1+2+4)-4×2=-15又1/4

再答：第9行，第一列再答：上面一行，粘贴错了，只看图片再答：采纳一下，好吗？谢谢了

(x+1)²-(x-1)(x²+x+1)=x²+2x+1-（x³-1)=-x³+x²+2x+2=-x(x²-x-2)+2=-x(x

（x平方-4x+4分之x平方-4）-（x+2分之x-2）=[(x+2)(x-2)]/[(x-2)^2]-(x-2)/(x+2)=(x+2)/(x-2)-(x-2)/(x+2)=[(x+2)^2-(x-

x平方-2x/x平方-1除以[(x-1)-(2x-1/x+1)]=[x(x-2)/(x+1)(x-1)]/[(x^2-1-2x+1)/(x+1)]=x(x-2)/(x+1)(x-1)×(x+1)/x(

√x^-2xy+y^2+x^2-6xy+9y^2/x-3y=√(x-y)^2+(x-3y)^2/x-3y由于y>x=y-x+x-3y=-2y=-2√5

（x-（x-4)/(x-3））÷（x-4）/（x-3）=（x²-4x+4）/（x-3)×（x-3）/（x-4）=（x-2)²/（x-4）.所以当x=根5时,原式=（根5-2）

原式=[3x/(x-1)-2x/(x+1)]*(x+1)(x-1)/x=3x/(x-1)*(x+1)(x-1)/x-2x/(x+1)*(x+1)(x-1)/x=3(x+1)-2(x-1)=3x+3-2

X+2分之X*2+4X+4除于（X*2+2X）=(x+2)^2/(x+2)÷(X*2+2X)=(x+2)×1/x(x+2)=1/x=1/√2=√2/2

原式=（x-2+2x+4)/(x+2)(x-2）*x(x+2)/3x+2)=x/(x-2)当x-2+根号3时,原式=（2+根号3）/（2+根号3）-2=（2根号3+3）/3

x²-1/x-1+x（1+1/x）=(x+1)(x-1)/(x-1)+(1*x+1/x*x)=x+1+x+1=2(x+1)=2√2

原式=x√x-3√(xy)代入数值=√2/4-3√6/2

(x²-6x+9)/(2x-6)=(x-3)²/[2(x-3)]=(x-3)/2=(5-3)/2=2/2=1很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按

求值9x+6x

原式=9x+6x2-3x+2x2=8x2+6x当x=-2时原式=8×（-2）2+6×（-2）=32-12=20．

1、x/9(x-y)^2*(x-y)+(x^2+2-x-y)/(x+y)=x/9(x-y)+(x^2+2)/(x+y)-2=[(x(x+y)+9(x-y)(x^2+2)]/9(X-Y)(X+Y)-2=

题目不是很清楚,里面该加括号的加起来再算

【（x的平方+5x+6）/（x+3）/（x平方-4）/（x-3)】-1=【（x+2）（x+3）/（x+3）/（x平方-4）/（x-3)】-1=【（x+2）/（x+2）（x-2）/（x-3)】-1=【1