化简求值 x的平方减1分之x除以-搜答案-神马作文网

1/(1-x+2)/(x^2+2x+1)/(x^2-4),其中x=-3=1/(3-x)*(x+2)(x-2)/(x+1)^2=(x+2)(x-2)/(x+1)^2(3-x)=5/24

因为x=1+根号2y=1减根号2所以xy=1+根号2乘以1减根号2=1-2=-1x+y=2所以可以求得,原式=xy/(x+y)=-1/2

是(x^2/(x-1)-x+1)/(4x^2/(1-x)-4x+1)吗原式=(x-x+1)(x+x-1)/(x-1)/((4x^2-4x+1+4x^2-x)/(1-x))=-(2x-1)/(4x^2-

(x+1)分之1-(x²-6x+9)分之(3-x)÷(x-3)分之(x²+x)=(x+1)分之1-(x-3)²分之[-(x-3)]÷(x-3)分之[x(x+1)]=(x+

原式=(x+1)/x÷(2x²-1-x²)/2x=(x+1)/x÷(x²-1)/2x=(x+1)/x÷(x+1)(x-1)/2x=(x+1)/x*2x/(x+1)(x-1

x的平方-2+x分之1-x除以(x-2+x+2分之3),其中x等于2分之1=(1-x)/(x²-2+x)÷[x-2+3/(x+2)]=(1-x)/(x+2)(x-1)÷(x²-4+

(x-1/x)/((x²-2x+1)/x)=((x²-1)/x)/((x-1)²/x)=(x+1)(x-1)/(x-1)²=(x+1)/(x-1)=6/4=3/

(xy-x的平方）除以xy分之x的平方-2xy+y的平方乘x的平方分之x-y=x(y-x)*xy/(x-y)²*（x-y）/x²=-y再问：不好意思，打错了(xy-y的平方）除以x

(xy-x²)÷(x²-2xy+y²)/(x-y)×(x-y)/x²=-x(x-y)÷(x-y)²/x²=-x(x-y)×x²/(

原式=(2-x-x-2)/(x+2)*(x+2)(x-2)/2x=-2x/(x+2)*(x+2)(x-2)/2x=-1/(x-2)=-1/(2-√2-2)=√2/2

你的式子太乱了,而且开头就是x=,分子分母分别用括号括起来,加减时也用括号括起来,一部分一部分的写清楚些再问：题目就是这样再答：那你看一下是不是我写的这个式子：x=((2-x-1)/2)/(x^2-(

x²-2x2x-1————÷(x-1-———)x²-1x+1x²-2x(x+1)(x-1)-(2x-1)=————÷————————x²-1x+1x²

[（x-1)/x-(x-2)/(x+1)]÷[(2x^2-x)/(x^2+2x+1)]=[(x-1)(x+1)-x(x-2)]/x(x+1)÷[x(2x-1)/(x+1)^2=(2x-1)/x(x+1

/>（2x-x分之1+x的平方）除以x分之x-1,其中x=根号2=[2x²-(1+x²)]/x÷(x-1)/x=(x²-1)/(x-1)=(x-1)(x+1)/(x-1)

（1+(x-1分之1））除以（x的平方-1）分之x=x-1分之x乘以x分之(x+1)(x-1)=x+1额,x的值呢?

分子分母同乘以4.再一化简

能把等式照下来吗

[1/(x+1)+(x^2-2x+1)/(x^2-1)]÷（x-1)/(x+1)=[1/(x+1)+(x-1)^2/(x+1)(x-1)]*(x+1)/(x-1)=[1/(x+1)+(x-1)/(x+

(x²+2x+1)分之(x+4)÷(x-2)分之x÷[x分之(x-2)×(x+1)分之(x+4)]=(x+1)²分之(x+4)×x分之(x-2)÷[x(x+1)]分之[(x-2)(