化简代数式x^2-1 x^2 3x
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原式=(x+1)(x-1)/x(x+2)*x/(x-1)=(x+1)/(x+2)∵x+2-2∴组的解集:-2
原式=(x^2-1)/(x^2+2x)*(x-1)/x=(x-1)^2(x+1)/x^2(x+2),解不等式组:x+2>1,——》x>-1,2(x-1)>-6,——》x>-2,所以,解集为:x>-1,
求代数式x2+4+(12−x)2+9,即(x−0)2+(0−2)2+(12−x)2+(3−0)2的最小值,实际上就是求x轴上一点到(0,-2)以及(12,3)两点的和的最小值,而两点间的距离是线段最短
再答:望采纳,谢谢
原式=(x²-2)/(x+1)(x-1)÷[(x²-1-2x+1)/(x+1)=(x²-2)/(x+1)(x-1)×(x+1)/(x²-2)=1/(x-1)
[1/(x-1-1/(x+1)]÷x/(x^2-1)=[(x+1)-(x-1)]/(x+1)(x-1)*[(x+1)(x-1)/x]=[2/(x+1)(x-1)]*[(x+1)(x-1)/x]=2/x
原式=2x²+x-kx²+3x²-x+1=(5-k)x²+1是负数则(5-k)x²+1
2x^5-5x^4-x^3+x^2-6x/(x^2+1)=2x^5-5x^4-x^3+x^2-6x/3x=2x^5-5x^4-x^3+x^2-2=2x^3(x^2-3x+1)+x^4-3x^3+x^2
3x/(4x+1)-2x/(5x-3)=3x(5x-3)/(4x+1)(5x-3)-2x(4x+1)/(4x+1)(5x-3)=(15x^2-9x-8x^2-2x)/(20x^2-7x-3)=(7x^
1-7x<3,-7x-2/7x+1>5/7;-3x>0x
x2−1x2+2x÷x−1x=x2−1x2+2x•xx−1=(x −1)(x+1)x(x +2)•xx−1=x+1x+2,不等式组x+2<1①2(x−1)>−6②,解不等式①,得x
1/x-1+1/x+1+2x/x²+1+4x³/x^4+1=(x+1+x-1)/(x-1)(x+1)+2x/(x²+1)+4x³/(x^4+1)=2x/(x
1-7x<3-5x2x>-2x>-1x+1>0-3x>0x
(2x²+x)-[kx²-(x²-x+1)]=2x²+x-(kx²-x²+x-1)=2x²+x-kx²+x²-
√[x+2√﹙x-1﹚]-√[x-2√﹙x-1﹚]=√[﹙x-1﹚+2√﹙x-1﹚+1]-√[﹙x-1﹚-2√﹙x-1﹚+1]=√[√﹙x-1﹚+1]²-√[﹙x-1﹚-1]²=|
∵x²-2x=2∴x²-2x+1=3即(x-1)²=3原式=(x-1)²+(x+3)(x-3)+(x-3)(x-1)=(x-1)²+(x-3)(x+3
解3(x-1)-(x-5)=3x-3-x+5=(3x-x)+(5-3)=2x+22(x²-y²)-3(x²-2y²)=(2x²-3x²)+(