利用一维数组输出fibonacci数列前20项每行输出5个数

#includeintmain(){intkey,index;intarr[10]={1,2,3,4,5,6,7,8,9,10};printf("输入整数Key:\n");scanf("%d",&ke

#include#include#includeintmain(){inta[15],i,j;srand(time(NULL));for(i=0;i<15;i++)a[i]=rand()%100;fo

#includeintmain(){inta[]={1,2,3,4,5,6,7,8,9,10},*p,i;p=a;for(i=0;i

刚刚我写了很详细来答你刚才的那个提问,但是,但是当我写完时,你已经选择了最佳答案了.inta[][10]这类数字上的数组我想应该比较好理解吧,难理解的是chara[][10]这类字符上的数组,我就拿你

#includevoidmain(){intn,i,j=0,a[1000];for(i=1;i

//有很多问题啊,帮你改了该,你自己参考看看吧.#include#includevoidmain(){intisbeishu(inti);inti;intj=0;//intb[50];for(i=1;

可用递归算法实现N重循环来实现详细请QQ:115499275以下也许有助于你以下为文件的内容:VERSION5.00BeginVB.FormForm1Caption="Form1"ClientHeig

char*s[12]={"Jan.","Feb.","Mar.","Apr.","May.","Jun.","Jul.","Aug.","Sep.","Oct.","Nov.","Dec."};int

因为f[100]是一个很大的数字,int根本就表示不下来,应该用大数的加法来做的#include#includevoidsum(chara[],charb[]){\x09inti,n,k;\x09fo

importjava.util.Scanner;publicclassQk{publicstaticvoidmain(String[]args){inti;System.out.println("请指

所要求的程序已经完成,#include<stdio.h>#include<stdlib.h>main(){ inta[100],i,s=0; randomi

function[a,b,c,d]=ff(A)a=max(A);b=min(A);c=mean(A);d=length(A);end

#include<stdio.h>void fanxu(int c[], int j);void main(){\x09int 

(**生成一维数组,存到C:/Users/zhou/Desktop/11.txt**)Data=Table[w,{w,0,1,0.01}]Export["C:/Users/zhou/Desktop/1

publicclassTest{publicstaticintfib(intn){if(n==1||n==2)return1;elsereturnfib(n-1)+fib(n-2);}publicst

#includemain(){inta[3][4]={{1,2,7,8},{3,4,9,10},{5,6,11,12}},b[4],i,j;for(j=0;j

voidmain(){floata[10];float*p=a,max,min,pj=0;inti=0,j;for(;i

inta[20];a[0]=1;a[1]=1;for(inti=2;ia[i]=a[i-1]+a[i-2];for(inti=0;i{for(intj=0;j

#includevoidinput(inta[],intn)//输入{inti;printf("请输入%d个数,用空格隔开\n",n);for(i=0;i

#include#include#defineN20voidmain(){inti,k,j,a[N];k=0;printf("Pleaseinputtwentynozeronumbers\n");fo