分式的加减x-1分之x 1-x平方-1分之4x

原式1/(x-1)+(x^2-3x)/(x+1)(x-1),然后通分得(x+1+x^2-3x)/(x+1)(x-1)=(x^2-2x+1)/(x+1)(x-1)=(x-1)(x-1)/(x-1)(x+

=x\(2-x)-(2+x)(2-x)\(2-x)^2=x\(2-x)-(2+x)\(2-x)=(x-2-x)\(2-x)=-2\(2-x)=2\(x-2)

x+1分之1+1-x分之1=(1-x)/(1+x)(1-x)+(1+x)/(1-x)(1+x)=2/(1-x²)m²-m分之1+2m²-2分之m-5=1/m(m-1)+(

[1/(x-y)-1/(x+y)]÷2y/(x^2-2xy+y^2)=[(x+y)/(x+y)(x-y)-(x-y)/(x+y)(x-y)]÷2y/(x-y)^2=[(x+y-x+y)/(x+y)(x

我整理下题目吧1.分子部分(3x+4)/(x^2-1)-2/(x-1)化简得到(x+2)/(x+1)(x-1)这部把第二部分分母变成和第一部分一样就可以分子部分(x+2)/(x^2-2x+1)整理得到

1/(x+1)-(x-3)/(x²-1)×(x²-2x+1)/[(x-1)(x-3)]=1/(x+1)-(x-3)/[(x+1)(x-1)]×(x-1)²/[(x-1)(

1.7y分之12x除以8x的平方Y=12x/7y×1/8x²y=3/14xy²2.x平方-1分之x的平方-2x+1除以x的平方+x分之x-1=(x-1)²/(x+1)(x

1.(1)2x-1/x-1(2)x^2-x+12.6x-x^2-1/x^3-1

-5x+1=0-5x=-1x=1/5(1/5)四次方=1/625+1/5=126/625所以x四次方+x=125/625

2/(x-y)-(x+y)/(x-y)^2=[(2x-2y)-(x+y)]/(x-y)^2=(x-3y)/(x-y)^2

(1)2xy/x-y+2y^2/y-x=2y(x-y)/x-y=2y(2)(x+y)*x^2/x^2-y^2+y^2/y-x=(x+y)*x^2/(x+y)(x-y)+y^2/y-x=x^2/x-y-

x/（2-x）-（2+x）.（2-x）/（（x+2）（x+2））=x/（2-x）-（2-x）/（x+2）=（6x-4）/（4-xx

原式=1/(x+1)*[(x-3)/(x+3)^2+2/(x+3)]-x/(x+3)(x-3)=1/(x+1)[3(x+1)/(x+3)^2]-x/(x+3)(x-3)=3/(x+3)^2-x/(x+

我帮你再问：好啊再答：先采纳再问：先给我再问：帮忙了啦再答：你不相信我？再问：算是吧再问：都是先采纳！你觉得我选哪个再答：我都读高二了，怎么可能不会这种题？再问：呵呵再答：采纳我吧！再问：答案再问：给

分式的加减（1）x-y分之3y-x的平方-xy分之2xy=3y/(x-y)-2xy/(x^2-xy)=3y/(x-y)-2y/(x-y)=y/(x-y)（2）b分之a-a分之b-ab分之a的平方+b的

4/a^2—1/a(a方分之四减a分之一)=（4-a)/(a*a)1/（x—3）—3/{x(x—3)}=(x-3)/(x*(x-3))=1/x

1.整理得到算式[2x-x+y]/[x^2-y^2]=[x+y]/[x+y][x-y]=1/[x-y]代入得到1/72.整理得到[1-3/(a+2)]/[(a^2-2a+1)/(a^2-4)]=[(a

我帮你再问：好啊再答：先采纳再问：先给我再问：帮忙了啦再答：你不相信我？再问：算是吧再问：都是先采纳！你觉得我选哪个再答：我都读高二了，怎么可能不会这种题？再问：呵呵再答：采纳我吧！再问：答案再问：给

计算过程见附件~~望采纳,谢谢~~