先化简,再求值:(x分之1-x 1分之1)

解x/(x+2)-(x²+2x+1)/(x+2)÷(x²-1)/(x-1)=x/(x+2)-(x+1)²/(x+2)÷(x-1)(x+1)/(x-1)=x/(x+2)-(

原式=[3x(x+1)-x(x-1)/x^2-1]×(x^2-1/2x)上面化到最后=[2x(x+2)/x^2-1]×x^2-1/2x=x+2当x=3时,原式=-3+2=-1(在键盘上打这个好辛苦啊~

x+2分之x-x+2分之x平方+2x+1除以x-1分之x平方-1=[x/(x+2)-(x²+2x+1)/(x+2)]÷(x²-1)/(x-1)=[(x-x²-2x-1)/

=x/(x-1)-x/(x+1)×(1-x)/2x=x/(x-1)+(x-1)/2(x+1)=[2x(x+1)+(x-1)²]/2(x-1)(x+1)=(3x²+1)/2(x

先化简,再求值:(x平方-1)分之(3x-3)÷(x+1)分之(3x)-(x+1)分之1,其中x=2=3(x-1)/(x+1)(x-1)×(x+1)/(3x)-1/(x+1)=1/x-1/(x+1)=

(x-1分之x平方-1-x分之2x)除以x-1分之x,其中x=根号3+1=[x²/(x-1)+2x/(x-1)]÷x/(x-1)=x(x+2)/(x-1)*(x-1)/x=x+2其中x=根号

你写的看不懂分子分母的代数式用括号括起来否则分不出来先通分【（（x-2）(x+2)-x(x-1)）/x(x+2)(x+2)】(x+2)/(x-4)=(x-4)/x(x+2)(x-4)=1/x(x+2)

(4x²-4x+2分之x)*(2x²-x)=(4x²-7x/2)*(2x²-x)=(x/2)(8x-7)(x)(2x-1)=x^2(8x-7)(2x-1)/2,

（1+1/(x-1))÷x/(x²-1)=x/(x-1)÷x/(x+1)(x-1)=x/(x-1)×(x+1)(x-1)/x=x+1代入可得结果等于-1

[4(x²-x)+(x-2)²]/(x-1)=(4x²-4x+x²-4x+4)/(x-1)=(5x²-8x+4)/(x-1)=[5(x-1)²

（1x2+4x+4+1x2+2x）÷x+1x+2=[1(x+2)2+1x(x+2)]×x+2x+1=2(x+1)x(x+2)2×x+2x+1=2x(x+2)，当x=3时，原式=23×(3+2)=215

1、(x-3分之2x-x+3分之x)乘x分之x平方-9=［2X(X+3)-X(X-3)］/［(X-3)(X+3)］*(X+3)(X-3)/X=［2X^2+6X-X^2+3X］/X=X+9当X=1时,原

（x-1分之3x-x+1分之x）*x分之x的平方-1=[3x(x+1)-x(x-1)]/x=3(x+1)-(x-1)=3x+3-x+1=2x+4=2√2-4+4=2√2再问：确定么再答：确定啊，楼下也

原式=(x-1)(x+1)/(x+2)*(x+2)/x-1=x+1然后代入数值即可很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,

因为(x-1/x)÷（x+1）/x=（x+1）（x-1)/x×x/（x+1）=x-1.所以当x=根2+1时,原式=根2..

[3x/(x-1)-x/(x+1)]×(x²-1)/x=x[3(x+1)-(x-1)]/(x²-1)×(x²-1)/x=2x+4当x=√2-2时,原式=2x+4=2√2

=（x+1）/（（2*x+1+x^2）/x）=（x+1）/（（x+1）^2/x）=（x+1）*x/（x+1）^2=x/（x+1）代入x=-3/2得到：原式=3

原式=2x+1÷4x(x+1)=2x+1×x(x+1)4=x2，当x=-2时，原式=-22=-1．

（x²-1分之x-3）÷（x²+2x+1分之x²-2x-3)-(x+1分之1）=(x-3)/(x+1)(x-1)×(x+1)²/(x-3)(x+1)-1/(x+