产生100个0到200之间的随机数在屏幕上
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窗体中加命令按钮,单击事件代码如下:PrivateSubCommand1_Click() Randomize Dima(1To20)AsInteger&nb
#include#include#include#includevoidsushu(int*a);intmain(){inta[50],i;intt=200,d=500;srand(time(NULL
Private Sub Command1_Click()Text1.Text = ""Dim A(1 To 1
import java.util.Random;public class EchoTest { public&nb
Dimb(100)PrivateSubCommand1_Click()Fori=1To100a=Int(1800*Rnd)+200b(i)=aPrintb(i)NextiEndSubb这个数组里面就保
packagetest;importjava.util.Random;publicclassrandomNum{publicstaticvoidmain(String[]args){chec
先在窗体上添加一个TextBox文本框(将其Multiline属性设置为True,并调整宽高以便能较好的显示出100个随机数)和一个Button按钮.然后双击Button按钮跳转到代码编辑窗口,粘帖以
#include#include#includeintmain(){inta,b,c;srand((unsigned)time(0));a=rand()%100+1;b=rand()%100+1;c=
121和169只有完全平方数的因数个数是奇数,而只有奇素数的平方才会只有三个因数,因此11的平方=12113的平方=169
#include#include#includevoidmain(){intnum;srand(time(0));num=rand()%100;printf("%d\n",num);}
Dimsum,max,minSubaaa(ByRefsum,ByRefmax,ByRefmin)min=100'给最小值先给一个比较大的值Fori=1To100s=Int(Rnd(1)*(67-0))
B=I2*g2;I3=int(B,L2,600,1600);%以上为第三次积分,未验证g1=(1/(44.036*sqrt(2*pi)))*exp((-0.5)*((L1-880.72)/44.036
//以下程序是产生0到9之间10个不重复的随机数.你参考一下,这个是我搜索的,你有什么问题搜索一下吧,或者到CSDN论坛上提问.#include//标准工具库,要用到其中的rand()#include
#include//提供printf函数声明定义#include//提供srand函数声明定义,rand#include//提供time函数intis_same(int*t,intlo,intx);i
#include<stdio.h>#include<stdlib.h>#include<time.h>#defineM20voidmain(){inta[M],i;
选择法:PrivateSubForm_Click()Dimi%,j%,a%(1To10)RandomizeFori=1To10a(i)=Int(101*Rnd)NextiFori=1To9k=iFor
PrivateSubCommand1_Click()Dima,b,cAsIntegerRandomizea=Int(Rnd*9)+1Randomizeb=Int(Rnd*9)+1Randomizec=
#include#includeintmian(void){intarr[50]={0};srand((unsignedint)time(NULL));intnIndex=0;for(;nIndex{
Option ExplicitPrivate Sub Form_Load()RandomizeMe.AutoRedraw = TrueDim 
#include#include#includevoidmain(void){inti;srand((unsigned)time(NULL));for(i=0;icout