(xy 2)(xy-2)-2x的2次方y的2次方 4)÷(负xy)
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(x+y)(xy)=x^2y+xy^2=-8原式=-7
由题意得,x-1=0,y+3=0,解得x=1,y=-3,所以,1-xy-xy2=1-1×(-3)-1×(-3)2,=1+3-9,=4-9,=-5.
因为化简后是二次多项式,所以,mx³+2x³=0,m=-2.3ny²x-xy²=0,n=1/3.2m+3n=-4+1=-3.
2(xy-5xy2)-(3xy2-xy)=(2xy-10xy2)-(3xy2-xy)=2xy-10xy2-3xy2+xy=(2xy+xy)+(-3xy2-10xy2)=3xy-13xy2,∵(x+1)
∵xy+x+y+7=0  
解-x²y-xy²=-xy(x+y)=-2×5=-10
a^x+4*b^y-1与a平方b^-x是同类项则:x+4=2y-1=-x解得:x=-2;y=35xy平方-2x平方y+3xy平方-4xy2+2x平方y=4xy²=4×(-2)×9=-72
是不是求:5x²y-[2x²-(3xy-xy²)-3x²]-2xy²-y²再问:是再答:已知是不是(x+3)²+|x+y+10|=
3xy(x²y-xy²+xy)-xy²(2x²-3xy+2x)=3x³y²-3x²y³+3x²y²-
∵2x+y=4,xy=3,∴2x2y+xy2=xy(2x+y)=3×4=12.故答案为:12
x=2013,y=2013[3x(x²y-xy²)+xy×(3xy-2x²)]/(x²y)=[3x²y(x-y)+x²y×(3y-2x)]/
(1)[1/(x-1)-1/(x+1)]*(x^2-1)/x=[x+1-(x-1)]/[(x-1)(x+1)]*(x^2-1)/x=[2/(x^2-1)]*[(x^2-1)/x]=2/x根据x=√5,
1)-x^2y-xy^2=-xy(x+y)=-2×3=-62)x²+5xy+30y=x(x+5y)+30y=6x+30y=6(x+5y)=6×6=36
x2y+xy2=xy*(x+y)因为x+y=-(7+xy)又x+y=(9+2xy)\3所以(9+2xy)\3=-(7+xy)3+2xy\3=-7-xy5xy\3=-10解得xy=-6所以x+y=-(7
xy³+xy²+xy=xy(y²+y+1)
因为x^2y+xy^2=30,xy(x+y)=30,xy=6x+y=5所以(x+y)^2=x^2+y^2+2xy=x^2+y^2+12=25所以x^2+y^2=13所以(x-y)^2=x^2+y^2-
原式=-xy(x-y),当x-y=3,xy=-2时,则原式=-3×(-2)=6.故答案为:6.
解2xy²-[3xy²-2(x²y-1/2xy²)]-2x²y=2xy²-(3xy²-2x²y+xy²)-2x
解3xy²-[2xy²-2(xy-1.5x²y)]+xy-3x²y=3xy²-(2xy²-2xy+3x²y)+xy-3x²
∵x+2y=5,xy=1,∴2x2y+4xy2=2xy(x+2y)=2×1×5=10,故答案为:10.