(x-2)y=y 2(x-2)^3的通解

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/23 19:21:22
(x-2)y=y 2(x-2)^3的通解
已知实数x,y满足x2+y2-2x+4y=0,则x2+y2的最小值是

再问:对不起题目打错了,是已知实数x,y满足x2+y2-2x+4y-20=0,则x2+y2的最小值是A.30-10√5B.5-5√5C.5D.25再答:更改后的答案:

已知x-y+1,X2+Y2=25 求(x+y)2和x2-xy+y2的值

x-y=1,(x-y)^2=x^2+y^2-2xy=12xy=25-1=24,xy=12(x+y)^2=x^2+y^2+2xy=25+24=49x^2-xy+y^2=25-12=13

x/x-y*y^2/x+y-x^3y2/x^4-y^4/x^2/x^2+y^2

写清楚点点比如说前面是X/X还是X/(X-Y)打上括号分段这样才能清楚的做

已知圆x2+y2-2x-2y+1=0求x2+y2的最大值

(x-1)^2+(y-1)^2=1令x-1=sinay-1=cosa则x=1+sina,y=1+cosax^2+y^2=1+2sina+(sina)^2+1+2cosa+(cosa)^2=3+2(si

已知x,y满足x2+y2-6x-2y+5=0,求x2+y2的最大值

x2+y2-6x-2y+5=0(x-3)^2+(y-1)^2=5表示一个圆,圆心坐标(3,1)x^2+y^2表示圆上一点(x,y)到原点的距离的平方.画图就看出,最大距离是:圆心到原点的距离+半径.即

已知X2+Y2+8X+6Y+25=0 求代数式X2++XY+4Y2分之X2-4Y2 减X+2Y分之X的值

X2+Y2+8X+6Y+25=0x²+8x+16+y²+6y+9=0(x+4)²+(y+3)²=0∴x+4=0y+3=0x=-4y=-3X2+4XY+4Y2分之

已知实数x,y 满足x2+y2+2x=0则x+y得最小值

设x+y=k,代入x2+y2+2x=0x2+(k-x)2+2x=0x2+k2-2kx+x2+2x=02x2-(2k-2)x+k2=0判别式=(2k-2)2-4*2k2>=04k2-8k+4-8k2>=

X2+Y2+8X+6Y+25=0 求代数式(x2-4y2/x2+4xy+4y2)-x/x+2y

X2+Y2+8X+6Y+25=0x^2+y^2+8x+6y+25=0x^2+8x+16+y^2+6y+9=0(X+4)^2+(y+3)^2=0x=-4y=-3(x^2-4y^2)/(x^2+4xy+4

已知两圆x2+y2-10x-10y=0,x2+y2+6x-2y-40=0,

(1)x2+y2-10x-10y=0,①;x2+y2+6x-2y-40=0②;②-①得:2x+y-5=0为公共弦所在直线的方程;(2)弦心距为:|10+5−5|22+12=20,弦长的一半为50−20

已知2x=3y,求xy/(x2+y2)-y2/(x2-y2)的值

已知2x=3y,求xy/(x^2+y^2)-y^2/(x^2-y^2)的值2x=3y-->x=(3/2)yx^2=(9/4)y^2xy/(x^2+y^2)-y^2/(x^2-y^2)==(3/2)y*

解方程组:y2=x3-3x2+2x;x2=y3-3y2+2y

y^2=x^3-3x^2+2xx^2=y^3-3y^2+2y两式相减得:y^2-x^2=(x^3-y^3)-3(x^2-y^2)+2(x-y)(x-y)(x^2+xy+y^2-2x-2y+2)=0所以

已知[(x2+y2)-(x-y)2+2y(x-y)]÷4y=1,求4x/4x2-4y2-1/2x+y的值,

[(x^2+y^2)-(x-y)^2+2y(x-y)]÷4y=1(x^2+y^2-x^2+2xy-y^2+2xy-2y^2)÷4y=1(4xy-2y^2)4y=12x-y=24x/(4x^2-y^2)

X二次方+2X+Y2次方-6Y+10=0,求x y值!

X二次方+2X+Y2次方-6Y+10=0x²+2x+1+y²-6y+9=0(x+1)²+(y-3)²=0x+1=0,y-3=0x=-1,y=3

正整数x,y满足x2-y2=2xy,求x-y/x+y的值

(X+Y)²=X²+Y²+2XY=X²+Y²+X²-Y²=2X²(X-Y)²=X²+Y²-

求函数f(x,y)=(x2+y2)2-2(x2-y2)的极值

x=0或x=整负根号下1-y方

已知:x=3,y=-5,x2-2xy+y2/x2-y2的值是

x²-2xy+y²/x²-y²=(x-y)²/(x-y)(x+y)=(x-y)/(x+y)因为x=3,y=-5,所以(3-(-5))/(3+(-5))

已知实数x,y满足x2+y2-2x+2y=6求x2+y2的最值

x2+y2-2x+2y=6(x-1)²+(y+1)²=2²所以可设x=1+2cosay=-1+2sina于是x²+y²=(1+2cosa)²

已知x2+y2=20,x2+xy-2y2=2(x+2y),求x+y的值

因为x2+xy-2y2=2(x+2y)即(x-y)(x+2y)=2(x+2y)所以x-y=2(x-y)2=x2-2xy+y2=4所以xy=(x2+y2-4)/2=(20-4)/2=8(x+y)2=x2

整数x,y满足x2-y2=2xy,求x-y/x+y的值

(x-y)/(x+y)=(x-y)(x+y)/[(x+y)^2]=(x^2-y^2)/[x^2+y^2+2xy]=2xy/[x^2+y^2+x^2-y^2]=2xy/(2x^2)=y/xx^2-y^2

已知x2+4y2+x2y2-6xy+1=0,求 x4-y4/2x-y 乘 2xy-y2/xy-y2 除以(x2+y2/x

因为x²+4y²+x²y²-6xy+1=0(x²-4xy+4y²)+(x²y²-2xy+1)=0(x-2y)²