(x y) 的三次方-4(x-y)的平方 4(x-y)
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原式=2xy(x²+2xy+y²)=2xy(x+y)²=2*2*4²=64
x^2=y+4,所以x^2-y=4y^2=x+4,所以y^2-x=4x^3-2xy+y^3=(x^3-xy)+(y^3-xy)=x(x^2-y)+y(y^-x)=4x+4yx^2=y+4,y^2=x+
4x的三次方y+4x的平方y的平方+xy的三次方=xy(4x^2+4xy+y^2)=xy(2x+y)^2肯定对望采纳
原式=2xy(4x²-2x-1)再问:求过程再答:没有提取公因式
已知x+y=1,则x^3+y^3+3xy=(x+y)(x^2-xy+y^2)+3xy=1×(x^2-xy+y^2)+3xy=x^2-xy+y^2+3xy=x^2+2xy+y^2=(x+y)^2=1^2
原式=(x^4+xy³)-(2y^4+2x³y)=x(x³+y³)-2y(x³+y³)=(x-2y)(x³+y³)=(x
xy的三次方-2x²y²+x的三次方y=xy(y²-2xy+x²)=xy(x-y)²
-4x的7次方y的16次方2-3/2x的9次方y的9次方1.58×10的9次方
(2x^4)y³-x³y^4=(x³y³)(2x-y)=(xy)³(2x-y)=4³×(1/16)=4
-4x的平方+16x=-4x(x-4)-4x的三次方y+16x的二次方=-4x²(xy-4)y的二次方-16xy的三次方=y²(1-16xy)提示:因式分解,运用提公因式法
再问:谢谢大神再答:有问题继续密我
x²y³-2x(4xy³)=x²y³-2x²y³=-x²y³
原式=(﹣4x²y)·(﹣x²y²)·2xy³=(﹣4)×(﹣1)×2×(x²y·x²y²·xy³)=8x的5次方·y的
(4x的三次方y+6x的二次方y的二次方-xy的三次方)÷2xy=xy(4x²+6xy-y²)÷2xy=2x²+3xy-0.5y²
=xy(4x²+4xy+y²)=xy(2x+y)²
4x的三次方y+4x²y²+xy的三次方=xy(4x²+4xy+y²)=xy(2x+y)²
x³y-xy³=xy(x²-y²)=xy(x+y)(x-y)
xy(x+y)²-4x³y³=xy[(x+y)²-4x²y²]=xy(x+y+2xy)(x+y-2xy)
x三次方-3x²y+3xy²+4x²y-xy²+y的三次方=x三次方+2xy²+x²y+y的三次方当x=-1,y=-3时原式=-1-18-3
x³-y³-x²y+xy²=(x³-y³)-(x²y-xy²)=(x-y)(x²+xy+y²)-xy