(a-2)x (a 2b)xy-x 2y 7不含二次项
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1=(x-z-2ab)/xy2=(a²-2ab+b²)/a-b=(a-b)²/a-b=a-
x^5n+x^n+1=x^5n+x^4n+x^3n-x^4n-x^3n-x^2n+x^2n+x^n+1=x^3n(x^2n+x^n+1)-x^2n(x^2n+x^n+1)+(x^2n+x^n+1)=(
A-2B=2x²+3xy+2y-1-2(x²-xy+x-1/2)=2x²+3xy+2y-1-2x²+2xy-2x+1=5xy-2x+2y=x(5y-2)+2y根
(1)3x2-1-2x-5+3x-x2=2x2+x-6;(2)(8a2b-5ab2)-2(3a2b-4ab2)=8a2b-5ab2-6a2b+8ab2=2a2b+3ab2.
对.前提是x不等于y
1.=3(a-b)/(10ab)*(25a^2b^3)/((a+b)(a-b))=15/2*(ab^2)/(a+b)2.=(x+2y)(x-2y)/(x+y)^2*2x(x+y)/(x+2y)=2x(
拆开,化简得原式=2打得太乱了,不大明白,是不是-2ab方+2(a方b+ab方)-2(a方b-1)
(1)-4a3b2+10a2b-2ab=-2ab(2a2b-5a+1);(2)6(x+y)2-2(x+y),=2(x+y)[3(x+y)-1],=2(x+y)(3x+3y-1);(3)-7ax2+14
【x²+xy/(x-y)】/【xy/(x-y)】=【x²(x-y)/(x-y)+xy/(x-y)】/【xy/(x-y)】={【x²(x-y)+xy】/(x-y)}/【xy
(1)x=y=-2时,A=2×(-2)^3+3×(-2)×(-2)+2×(-2)-1=-9,B=(-2)^2-(-2)×(-2)+(-2)-1/2=-5/2A-2B=-9+5=-4(2)A-2B=2x
第一题4b2-(a2+4)-4a=4b2-4-(a2+4a)=4(b2-1)-a(a+4)=4(b+1)(b-1)-a(a+4)第二题-4a3b3+6a2b-2ab=-2ab(a2b2-3a-1)第三
A+B=(x²-3xy+y²)+(2x²+xy-9y²)=x²-3xy+y²+2x²+xy-9y²=3x²-2
(1)原式=3x2-7x+4x-3+2x2=(3+2)x2+(-7+4)x-3=5x2-3x-3;(2)原式=2xy-y+-y-yx=xy;(3)原式=5a2b-15ab2-2a2b+14ab2=(5
-xy^2+2xy-x=-x(y^2-2y+1)=-x(y-1)^2如果本题有什么不明白可以追问,如果满意请点击“选为满意答案”
|x-2a|+(y+3)²=0所以x-2a=0,y+3=0x=2a,y=-3B-2A=(4x²-6xy+2y²-3x-y)-2(2x²-3xy+y²-
(1)(1-a)/(a^2-2a+1)=(1-a)/(1-a)^2=1/(1-a)(2)(3x-4y)/(8xy-6x^2)=(3x-4y)/[2x(4y-3x)]=-1/(2x)(3)2x^2y(x
(x-y)/x²÷(x²-2xy+y²)/xy×(xy-x²)=(x-y)/x²÷(x+y)²/xy×x(y-x)=(x-y)²/
如果-2x>-4,那么x>2.此命题是假如果-1/2a2b,此命题是真如果a>b,则ac^2>bc^2.此命题是假如果ac
x²-xy+4分之y²=x²-2×x×2分之y+(2分之y)²=(x-2分之y)²x²y-2xy²+y³=y(x
x²+3y-xy-3x=x³-x²-x+这里是加多少=x²-1-2xy+y=a²-b²-c²+2ab=,后面那里来的abc这些字母