20-9y-20y²等于零因式分解
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这是一个完全平方公式4(x+y)²-20(x+y)+25=[2(x+y)]²-2x5x2(x+y)+5²=[2(x+y)-5]²再问:能帮我讲解一下吗?再答:例
-y²/9-1+2y/3=-(y²/9-2y/3+1)=-(y/3-1)^2
解9(x-y)²-y²=[3(x-y)]²-y²=[3(x-y)-y][3(x-y)+y]=(3x-4y)(3x-2y)
y²-9(x+y)²=[y+3(x+y)][y-3(x+y)]=(y+3x+3y)(y-3x-3y)=-(3x+4y)(3x+2y)
1002x+2y+10
=(x-3y)²-3(x-3y)=(x-3y)(x-3y-3)
在实数范围内是没有解的只有在虚数范围内才有解(你确定?)再问:那用虚数怎么做呢再答:不用做了,考试一定不会出这种题的将x^2+25变成x^2-25就能做了(题目的可能写错了)5-x>0x
原式=24x+1+12²+4(x+y)²=【2²(x+y)²+12²】+24x+1=【2x+2y+12】²-48y-24x+1=【2x+2y
1-6y+y²=y²-6y+9-8=﹙y-3﹚²-8=﹙y-3-2√2﹚﹙y-3+2√2﹚.
9(x-y)^2+12(x^2-y^2)+4(x+y)^2=[3(x-y)]^2+2*3(x-y)*2(x+y)+[2(x+y)]^2=[3(x-y)+2(x+y)]^2=(5x-y)^2
(x+y)²-6x²+6y²+9(x-y)²=x²+2xy+y²-6x²+6y²+9x²-18xy+9y
原式=[3(x+y)]²-(x-y)²=[3(x+y)+(x-y)][3(x+y)-(x-y)]=(4x+2y)(2x+4y)=4(2x+y)(x+2y)
16(x-y)²+24(y²-x²)+9(x+y)²=[4(x-y)]²+2*4(x-y)*3(x+y)+[3(x+y)]²=[4(x-y)
16(x-y)²-9(x+y)²=【4(x-y)+3(x+y)】【4(x-y)-3(x+y)】=(7x-y)(x-7y)在我回答的右上角点击【评价】,然后就可以选择【满意,问题已经
(x+y)^4+(x+y)^2-20=[﹙x+y﹚²+5﹚][﹙x+y﹚²-4]=﹙x²+2xy+y²+5﹚﹙x+y-2﹚﹙x+y+2﹚
4(x+y)²-20(x+y)+25=[2﹙x+y﹚-5]²=﹙2x+2y-5﹚²
:a(3x+9y)-x-3y=3a(x+3y)-(x+3y)=(3a-1))(x+3y)
4x^4y^2-5x^2y^2-9y^2=y^2(4x^4-5x^2-9)=y^2(4x^2-9)(x^2+1)=y^2(2x-3)(2x+3)(x^2+1)
16(X+Y)平方-9(Y-X)平方=[4(x+y)]²-[3(y-x)]²=[4x+4y-3y+3x][4x+4y+3y-3x]=(7x+y)(x+7y)