2.1X-X=11 解方程
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/11 01:51:34
x/(2x^2-11x-21)=(x+7)/(x^2-12x+35)x/(2x+3)(x-7)=(x+7)/(x-5)(x-7)x/(2x+3)=(x+7)/(x-5)x(x-5)=(x+7)(2x+
X/(x-30)=(x+40)/XX^2=(X-30)*(X+40)X^2=X^2+40X-30X-120010X=1200X=120
【解法一】【解法二】5x(x+7)(x+4)=5x(x^2+11X)5x(x²+11x+28)-5x(x²+11x)=05x^3+55x^2+140x=5x^3+55x^25x(x
只有一个实根.设f(x)=x^3+2x-19为单调增函数.所以只有一个实根.下面来求这个实根由于f(2)=-7f(3)=11所以这个根在(2,3)内.利用二分法求这个解.取x0=5/2f(5/2)=1
x^3-x^2-2x=0x(x^2-x-2)=0x(x-2)(x+1)=0x=0或x=-1或x=2
6x²-9x-4x+2x²=-2x+8x²-11-9x-4x﹢2x=-11-11x=-11x=1
令2x-11=0,得x=11/2令x-3=0,得x=3令x-8=0,得x=8当x
本人提供一个解法:由于(x-2004)/(x-2005)=1+1/(x-2005),其它三个分式同样进行拆分,最终得出:[1+1/(x-2005)]-[1+1/(x-2006)]=[1+1/(x-20
x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)
x(2x-3)+3x+3x(x-2)=5x(x-4)+112x²-3x+3x+3x²-6x=5x²-20x+115x²-6x=5x²-20x+115x
4.2X-2.5-1.9X=2.12.3x=4.6x=2
原式=2.1X-1X=111.1X=11X=11/1.1X=10
(x+x)+(x-x)+(xx)+(x/x)=1002x+0+x²+1=100x²+2x+1=100(x+1)²=10²x+1=10或x+1=-10x=9或x=
x/(2x^2-11x-21)=(x+7)/(x^2-12x+35)x/(2x+3)(x-7)=(x+7)/(x-5)(x-7)约去x-7(显然x=7不是方程的根)x/(2x+3)=(x+7)/(x-
用换元法设x*x+11x-8=A然后再做
x²+3x-9=x-11x²+3x-x-9+11=0x²+2x+2=0Δ=2²-4*1*2=-4
变形为1/x-1/(x+1)+1/(x+1)-……+1/(x+9)-1/(x+10)=11/121/x-1/(x+10)=11/12x1=-5-1/11*4345^(1/2)x2=-5+1/11*43
再问:请给详细过程。再答: