2-log(x-16)=log(x-1)
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用换底公式log(3)4*log(4)8*log(8)M=(lg4/lg3)*(lg8/lg4)*(lgM/lg8)=lgM/lg3log(2)16=log(2)2^4=4lgM/lg3=4lgM=4
log(x+5)=log(x)+log(2)log(x+5)=log(2x)x+5=2xx=5log(8)+log(x)=log(24)log(8x)=log(24)8x=24x=32log(x)=l
log(2)[log(3)(log(4)x)]=0log(3)(log(4)x)=1log(4)x=3x=64log(3)[log(4)(log(2)y)]=0log(4)(log(2)y)=1log
log(3x)²=log4(6-x)所以9x²=24-4x9x²+4x-24=0x=(-2±2√55)/9真数3x>0,6-x>0所以x=(-2+2√55)/9再问:lo
loga2
没有底数吗?还是是lg[(lg(x^2)+lg(x^4))/lg(100x)]=(2lgx+4logx)/lg(100x)=6lgx/(2+lgx)=46lgx=8+4lgx所以.lgx=4x=100
原式为2㏒(3)x+㏒(3)2=1/2log(3)16化简:log(3)x²+log(3)2=log(3)4log(3)x²+log(3)2=2log(3)2log(3)x
log2x2=22x2=100x2=50x=正负5倍根号2x2指X的平方
log(2)(25)×=lg25/lg2=2lg5/lg2log(3)(1/16)=lg(1/16)/lg3=-4lg2/lg3log(5)(1/9)=lg(1/9)/lg5=-2lg3/lg5log
比如log(9)a=log(3)a/[log(3)9]=log(3)a/2=log(3)[a^1/2]换底公式而log(2)[16]=log(2)[2^4]=4log(2)2=4
f(x)=log^2(x+1)/(x-1)+log^2(x-1)+log^2(p-x)定义域:(x+1)/(x-1)>0,且x-1>0,且p-x>0x<-1或x>1,且x>1,且x<p∴1<x<pf(
如果数据没错的话应该就是这个答案了.
㏒(X+5)(X+2)=1,X^2+7X+10=10X=0或X=-7,当X=0时,符合题意,当X=-7时,㏒(X+5)无意义,舍去.∴X=0.
log₂log₃log₄X=0log₃log₄X=1log₄X=3X=64log₃log₄logS
log(2)4·log(4)8·log(8)m=log(4)16lg4/lg2*lg8/lg4*lgm/lg8=2lgm/lg2=2log(2)m=2m=2平方=4
log1/7[log3(log2x)]=0=log1/7(1)所以log3(log2x)=1log3(log2x)=log3(3)log2(x)=3x=2³x=8
使用换底公式log(27)16/log(3)4=(lg16/lg27)/(lg4/lg3)=(lg16/lg27)*(lg3/lg4)=(2lg4/3lg3)*(lg3/lg4)=2/3
f(√5)=2log(5)√5=2*1/2=1
2log(b)x=log(a)x+log(c)x2lgx/lgb=lgx/lga+lgx/lgc把lgx约分2/lgb=1/lga+1/lgc=(lga+lgc)/(lgalgc)=lg(ac)/(l