(5x+6xy)-8y²计算
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/20 18:56:21
-x^y^7+y^8)(这里有问题,x的几次方?再问:就是一次方再答:(x^8-x^7y+x^5y^3-x^4y^4+x^3y^5-xy^7+y^8)(x^2+xy+y^2)=(x^8-x^7y+x^
1.x^4+5x^2-6=(x^2+6)(x^2-1)=(x^2+6)(x-1)(x+1)2.(x+y)(x+y+2xy)+(xy+1)(xy-1)=(x+y)^2+2xy(x+y)+(xy+1)(x
3xy[2xy-x(y-2)+x-1]=3xy(2xy-xy+2x+x-1)=3xy(xy+3x-1)=3x^2y^2+9x^2y-3xy
3x/8y×16y²/27x²=2y/9x(2xy-x²)÷x-2y/xy=-x(x-2y)×xy/(x-2y)=-x²y2x-6/x²-4x+4×2
(1)3x/8y×16y²/27x²=(3/8×16/27)×(y/x)=2y/9x(2)(2xy-x²)÷x-2y/xy=x(2y-x)×[xy/(x-2y)]=-x&
3xy[2xy-x(y-2)+x]=3xy[2xy-xy+2x+x]=3xy(xy+3x)=3x²y²+9x²y
5x^2-13xy-8y^2
这题少括号了吧.
(5-xy/x^3-x^2y)/(1-5/xy)^2*(y-x)^3=-(x-y)^3[-(xy-5)/x^2(x-y)]/[(xy-5)/xy]=(x-y)^3(xy-5)xy/x^2(x-y)(x
计算:(6x^5-7x^4y+x^3y^2+20x^2y^3-22xy^4+8y^5)/(2x^2-3xy+y^2)列竖式相除就行,要点是每除一步必须减少被除式中的一项.结果是商式为3x^3+x^2y
【x²+xy/(x-y)】/【xy/(x-y)】=【x²(x-y)/(x-y)+xy/(x-y)】/【xy/(x-y)】={【x²(x-y)+xy】/(x-y)}/【xy
(xy-y^2)÷x-y/xy=y(x-y)×[xy/(x-y)]=xy²
5x3次方y*(-3y)²-6x²y²*(-xy)=5x^3*y*9y^2+6x^3y^3=45x^3y^3+6x^3y^3=51x^3y^3不懂可追问,有帮助请采纳,谢
=x^3-y^3-(x^3+y^3)=-2y^3^3表示三次方
原式=-3+6x^2y^2-x原式=8(x-y)(x^2-y^2)^3/27[x^2-y^2]^3=8(x-y)/27=8/27x-8/27y
(5xy+4x+7y)+(6x-3xy)-(4xy-3y)=5xy+4x+7y+6x-3xy-4xy+3y=(5xy-3xy-4xy)+(4x+6x)+(7y+3y)=-2xy+10x+10y=-2x
(xy-x²)乘(x-y)分之xy=-x(x-y)乘[(x-y)分之xy]=-x²y
(2X平方y+3xy平方)-(6x平方-3XY平方)=2x²y+3xy²-6x²+3xy²=2x²y+6xy²-6x²
解(x-y)/(xy-y²)=(x-y)/y(x-y)=1/y
6x³y(x-y)³-4xy³(y-x)²=6x³y(x-y)³-4xy³(x-y)²=2xy(x-y)²[3