(3x-2) (y-2)=0,求6x和y的值

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(3x-2) (y-2)=0,求6x和y的值
已知x-3y=0,求(2x+y)/(x^2-2xy+y^2)X(x-y)

(2x+y)/(x^2-2xy+y^2)X(x-y)=(2x+y)/(x-y)²*(x-y)=(2x+y)/(x-y)x-3y=0,x=3y(2x+y)/(x-y)=(6y+y)/(3y-y

已知|2x-3y|+|3x-y-1|=0,求x,y的值.

2x-3y=0(1)3x-y-1=0(2)由(2)得y=3x-1(3)把y=3x-1代入(1)得2x-9x+3=0∴x=3/7把x=3/7代入(3)得y=2/7∴x=3/7y=2/7

已知x>0 y>0 (2x+3y)(3x+2y)=75 求x+y的最小值.

75=(2x+3y)(3x+2y)  =6x^2+13xy+6y^2  =6(x+y)^2+xy>=24xy+xy=25xyxy<=3x+y>=2vxy=2v3最小值2v3再问:6(x+y)^2+xy

|3x-y+5|+(2x-y+3)²=0 求x=?y=?

由题意可得如下方程组:3x-y+5=02x-y+3=0解得:x=-2y=-5/2再问:很可惜思路对了得数错了Y=-1你是第一个回答我的还是选你吧

若2x平方+3xy-2y平方=0,求x+y/x-y

原方程左边=(2x-y)(x+2y)=0所以x=y/2或x=-y/2将x的值分别代入到x+y/x-y得-3或-1/3

已知4x-2y=0,求x-y/3x+2y的值

4x-2y=0→y=2x,把所有的y都用2x替代.结果是-1/7

|x-2y|+√3x-4y =0求x y值

绝对值和开根号都是大于等于0的,他两相加等于0说明都是0,分别算就行了,xy都是0

x-3y=0,求2X+5Y\3X-2Y

x=3y所以原式=11y/7y=11/7

已知X-Y/X+Y=3,求代数式2(x-y)/X+Y-3X+Y/X+Y

X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1

已知2x+3y=2(x>0,y>0),求x+y最大值

2x=2-3yx>0则2x>0所以2-3y>0y

已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)

因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6

已知3x^2+xy-2y^2=0,求{(x+y)/(x-y)+4xy/(y^2-x^2)}/{(x+3y)*(x-y)}

3x^2+xy-2y^2=0推出(3x-2y)(x+y)=0推出x=-y或x=(2/3)y{(x+y)/(x-y)+4xy/(y^2-x^2)}/{(x+3y)*(x-y)}/x^2-9y^2推出:{

|x+2y+3|+(2x+y)²=0求x²-xy+y²

解,因为|x+2y+3|+(2x+y)²=0所以|x+2y+3|=0,(2x+y)²=0所以:x+2y+3=0.2x+y=0解得x=1y=-2x²-xy+y²=

已知x-3y=0,求(2x+y)/(x^2-2xy+y^2)*(x-y)的值

2x+y/x^2-2xy+y^2)*(x-y)=2x+y/(x-y)^2*(x-y)=2x+y/x-yx-3y=0.x=3y将x=3y带入2x+y/x-y=6y+y/3y-y=7/2(二分之七)

已知x-3y=0,求(2x+y)/(x^2-2xy+y^2)*(x-y)的值.

x=3y代入(2x+y)/(x^2-2xy+y^2)*(x-y)=7y/(9y^2-6y^2+y^2)*(2y)=7/2

已知x-3y=0,求(2x+y)(x-y)/x^2-2xy+y^2的值

x-3y=0x=3y原式=(2x+y)(x-y)/(x²-2xy+y²)=(2×3y+y)(3y-y)/[(3y)²-2×3y×y+y²]=7y×2y/(9y&

若2x-3y=0,求5x+4y/3x-2y

2x-3y=02x=3yx=1.5y5x+4y/3x-2y=7.5y+4y/4.5y-2y=11.5y/2.5y=4.6

已知x,y>0 2x+y+3=xy 求5x+4y最小值

2x+y+3=xy,①若x=1,则y不存在,此时5x+4y无最值;②若x≠1,则y=(2x+3)/(x-1),M=5x+4y=5x+(8x+12)/(x-1)=(5x²+3x+12)/(x-

已知x^2-3y^2=2xy(x>0,y>0),求代数式x+2y/x-y

∵x^2-3y^2=2xy∴x^2-2xy-3y^2=0∴(x+y)(x-3y)=0∵x>0,y>0∴x-3y=0∴x=3y∴x+2y/x-y=3y+2y/3y-y=2y+2/3或=2/3(x+1)如