(25.4-4m)÷4解
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/22 19:34:56
[(m-2)/(m+2)+4m/(m²-4)]÷[1/(4-m²)]=[(m-2)²+4m]/(m+2)(m-2)×(2-m)(2+m)=-(m²-4m+4+4
原式=m-{3n-4m+[m-5m+5n+m]}=m-{3n-4m+5n-3m}=m-3n+4m-5n+3m=8m-8n.故答案为:8m-8n.
(m+2/m²-2m)-(m-1/m²-4m+4)÷(m-1/m)=(m+2)/m(m-2)-(m-1)/(m-2)^2*m/(m-1)=(m+2)/m(m-2)-m/(m-2)^
(m+3m+5m+.+2009m)-(2m+4m+6m+.+2008m)=2009m
=m(m-2)/(2-m)(2+m)=-m/(m+2)
3m-2m=m5m-4m=m……2009m-2008m=m相当于m+m+m+……m总共2009答案2009m
(4m²-4m+1)/(m+1)÷(4m²-1)/(m²-1)=(2m-1)²/(m+1)×(m+1)(m-1)/(2m+1)(2m-1)=(2m-1)(m-1
按照系数大小重新排序m-2m+3m-4m……+2009m-2010m+2010m每两项组成一组结果为1005个-m加2010m=1005m
=(m-2)²/(m+1)(m-1)*(m+1)/m-2+2/m-1=(m-2)/(m-1)+2/m-1=m/m-1=2
(m+3m+5m+...+2009m)-(2m+4m+...+2008m)=m+(3-2)m+(5-4)m+……+(2009-2008)m=m+m+m+……+m=1005m嗯再问:有没有可能的-100
m-2m-3m+4m-5m-6m+7m.2004m=(1-2-3+4-5-6+7-8-9+...2002-2003-2004)m=(-4-7-10-..-2005)m=-(4+7+10+..+2005
(m+3m+5m+...+2009m)-(2m+4m+6m+...+2010m)=2010m/2=1005m
(m+3m+5m+...+2013m)-(2m+4m+6m+...+2012m)=(2013m-2012m)+(2011m-2010m)+...+(5m-4m)+(3m-2m)+m=m+m+...+m
(m2013m)*1007/2-(2m2012m)*1006/2=1007m
原式=m+3m+5m+.2014m-2m-4m-6m-.2013m=m-2m+3m-4m+5m-6m=m+(3m-2m)+(5m-4m)+(2014m-2013m)=m+m+.1007个m=1007m
=m+(3m-2m)+(5m-4m)+……+(2015m-2014m)=m+1007m=1008m
有规律的,自己仔细看看~
原式=-(m+4)(m-4)/(m+4)²×2(m+4)/(m-4)×(m-2)/(m+2)=-(m-4)/(m+4)×2(m+4)/(m-4)×(m-2)/(m+2)=-2×(m-2)/(
m2(m+4)+2m(m2-1)-3m(m2+m-1)=m3+4m2+2m3-2m-3m3-3m2+3m,=m2+m,当m=25时,原式=425+25=1425.